5v^2+80v=0

Solution for 5v^2+80v=0 equation:

5v^2+80v=0

a = 5; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·5·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*5}=\frac{-160}{10}
=-16
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*5}=\frac{0}{10}
=0
$